Question

jquery easyui datagrid 通过spring2.5.6 mvc 来传输数据，页面url改如何写，Controller里面如何写？

我的Controller代码：
@RequestMapping("/right1.do")
public void right1(HttpServletRequest request,
HttpServletResponse response, ModelMap model) {
String text = "["
+ "{'code':'001','name':'Name 1','addr':'Address 11','col4':'col4 data'},"
+ "{'code':'002','name':'Name 2','addr':'Address 13','col4':'col4 data'},"
+ "{'code':'003','name':'Name 3','addr':'Address 87','col4':'col4 data'},"
+ "{'code':'004','name':'Name 4','addr':'Address 63','col4':'col4 data'},"
+ "{'code':'005','name':'Name 5','addr':'Address 45','col4':'col4 data'},"
+ "{'code':'006','name':'Name 6','addr':'Address 16','col4':'col4 data'},"
+ "{'code':'007','name':'Name 7','addr':'Address 27','col4':'col4 data'},"
+ "{'code':'008','name':'Name 8','addr':'Address 81','col4':'col4 data'},"
+ "{'code':'009','name':'Name 9','addr':'Address 69','col4':'col4 data'},"
+ "{'code':'010','name':'Name 10','addr':'Address 78','col4':'col4 data'}"
+ "]";
JSONObject json = new JSONObject();
try {
json.put("total", "23");
json.put("rows", text);
} catch (JSONException e) {
e.printStackTrace();
}
System.out.println(json.toString());
ResponseUtils.renderJson(response, json.toString());
}

这样写页面如何获取值？
发送json的方法：
public static void renderJson(HttpServletResponse response, String text){
response.setContentType("application/json;charset=UTF-8");
response.setHeader("Pragma", "No-cache");
response.setHeader("Cache-Control", "no-cache");
response.setDateHeader("Expires", 0);
try{
response.getWriter().write(text);
}catch(IOException e){
log.error(e.getMessage(), e); }}
页面用ajax测试通过：
var url1 = "${base}/jeeadmin/jspgou/right2.do";
$.get(url1,function(data){alert(data.rows);},"json");
能成功打印data.rows数据；
用easyUI接收数据无反应，代码如下：
$('#tt').datagrid({
url:"${base}/jeeadmin/jspgou/right2.do",
columns:[[
{field:'code',title:'Code',width:100},
{field:'name',title:'Name',width:100},
{field:'price',title:'Price',width:100}
]]
});
});

Answer 1

我也用springMVC写的代码，一般Controller里面这么写的：
@RequestMapping(value = "/mng/getappinfo", method = RequestMethod.POST)
@ResponseBody //别人跟我说加了这行返回json数据，不加只有上面那行会返回一个页面
public griddata getAppInfo(
@RequestParam(value = "user", required = false) String user,
@RequestParam(value = "roleid", required = false) String roleid){
griddata gdata = new griddata(appInfoService.getAppInfo(user));//这里从数据库获取字段，是个list
return gdata;
}

// 下面这个是griddata的类
public class griddata {
public griddata() {
super();
}
public griddata(List rows) {
super();
this.rows = rows;
}
private List rows;
public List getRows() {
return rows;
}
public void setRows(List rows) {
this.rows = rows;
}
}

js里面的代码应该都差不多

可以参考一下我这边的写法

Answer 2

返回的数据格式：sb.append("{\"total\" : " + totalRecord + ",\"page\" : " + page
+ ",\"records\" : " + totalPage + ",\"rows\" : [");
for (Menu menu : list) {
sb
.append(String
.format(
"{\"mid\": %s,\"name\":\"%s\",\"url\":\"%s\",\"target\":\"%s\",\"description\":\"%s\",\"parent\":\"%s\"},",
menu.getMid(), menu.getName(), menu
.getUrl(), menu.getTarget(),
menu.getDescription(), menu.getParent()));
}
if (!list.isEmpty()) {
sb.deleteCharAt(sb.length() - 1);
}
sb.append("]}");
页面数据。$(function(){
$('#test').datagrid({
title:'easyui演示',
iconCls:'icon-save',
width:750,
height:400,
nowrap: false,//True 就会把数据显示在一行里。
striped: true,//True 就把行条纹化。（即奇偶行使用不同背景色）
collapsible:true,
url:'demoPage.bo',
sortName: 'mid',//可以排序的列
sortOrder: 'asc',//升序或者降序排
remoteSort: true,//定义是否充服务器给数据排序
singleSelect:false,//是否单选
idField:'mid',//标识字段
loadMsg:'数据加载中....',
pageSize:10,
searchbox : true,
pageList:[10,20,50],
我只打了一部分，参照一下。

Answer 3

cf的玩那里多GP比叫多啊