
已知a=√3,求1-2a+a²/a-1-√a²-2a+1/a²-a-1/a的值
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a=√3>1,a-1>0
(1-2a+a²)/(a-1)- √(a²-2a+1)/(a²-a) -1/a
=(a-1)²/(a-1)- √(a-1)²/[a(a-1)] -1/a
=a-1 -(a-1)/[a(a-1)] -1/a
=a-1 -1/a -1/a
=a-1- 2/a
=√3 -1 -2/(√3)
=√3 -1-2√3/3
=√3/3 -1
(1-2a+a²)/(a-1)- √(a²-2a+1)/(a²-a) -1/a
=(a-1)²/(a-1)- √(a-1)²/[a(a-1)] -1/a
=a-1 -(a-1)/[a(a-1)] -1/a
=a-1 -1/a -1/a
=a-1- 2/a
=√3 -1 -2/(√3)
=√3 -1-2√3/3
=√3/3 -1
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元素=(a-1)²/(a-1)-√(a-1)²/a(a-1)-1/a
=a-1-|a-1|/a(a-1)-1/a
=a-1-(a-1)/a(a-1)-1/a
=a-1-1/a-1/a
=a-1-2/a
=√3-1-2/√3
=√3/3-1
=a-1-|a-1|/a(a-1)-1/a
=a-1-(a-1)/a(a-1)-1/a
=a-1-1/a-1/a
=a-1-2/a
=√3-1-2/√3
=√3/3-1
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解:a=√3>1,a-1>0
(1-2a+a²)/(a-1)- √(a²-2a+1)/(a²-a) -1/a
=(a-1)²/(a-1)- √(a-1)²/[a(a-1)] -1/a
=a-1 -(a-1)/[a(a-1)] -1/a
=a-1 -1/a -1/a
=a-1- 2/a
=√3 -1 -2/(√3)
=√3 -1-2√3/3
=√3/3 -1
(1-2a+a²)/(a-1)- √(a²-2a+1)/(a²-a) -1/a
=(a-1)²/(a-1)- √(a-1)²/[a(a-1)] -1/a
=a-1 -(a-1)/[a(a-1)] -1/a
=a-1 -1/a -1/a
=a-1- 2/a
=√3 -1 -2/(√3)
=√3 -1-2√3/3
=√3/3 -1
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