Question

求这道C语言题目的分析

#include <stdio.h>

int main()
{
static float score[][4] = {{60,70,80,90},{50,89,67,88},{34,78,90,66}};
float *search();
float *p;
int i,j;
for(i=0;i<3;i++)
{
p=search(score+i);
if(p==*(score+i))
{
printf("No.%d scores:",i);
for(j=0;j<4;j++)
{
printf("%5.2f ",*(p+j));
}
printf("\n");
}
}
}
float *search(pointer)
float (*pointer)[4];
{
int i;
float *pt;
pt = *(pointer+1);
for(i=0;i<4;i++)
{
if(*(*pointer+i)<60)
{
pt=*pointer;
}
}
return(pt);
}

我十分不理解这里的
float *search(pointer)
float (*pointer)[4];
这是函数名还是神马？

Answer 1

float *search(pointer)
float (*pointer)[4];
这是老式的函数头部,现在大多数编译器已不支持这种写法,现代的写法应该是
float *search(float (*pointer)[4])