Question

求导数的题 设x=1/(t^2-1),求dx,详细过程,谢谢...O(∩_∩)O

Answer 1

x=(t^2-1)^(-1)
dx=-1(t^2-1)^(-2)d(t^2-1)
=-(t^2-1)^(-2)*(2t)dt
=[-2t/(t^2-1)^2]dt