设关于x的不等式丨x-(a+1)^2/2丨≤(a-1)^2/2的解集为A，x^2-3(a +1)x+2（3a+1）≤0的解集为B
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-(a-1)²/2<=x-(a+1)²/2<=(a-1)²/2
-(a-1)²/2+(a+1)²/2<=x<=(a-1)²/2+(a+1)²/2
2a<=x<=a²+1
(x-2)[x-(3a+1)]<=0
a=1/3,则x=2
不满足2a<=x<=a²+1
a<1/3，3a+1<=x<=2
则有2a<=3a+1且2<=a²+1
所以a=-1
a>1/3，2<=x<=3a+1
则有2a<=2且3a+1<=a²+1
这个不鞥同时成立
所以a=1
-(a-1)²/2+(a+1)²/2<=x<=(a-1)²/2+(a+1)²/2
2a<=x<=a²+1
(x-2)[x-(3a+1)]<=0
a=1/3,则x=2
不满足2a<=x<=a²+1
a<1/3，3a+1<=x<=2
则有2a<=3a+1且2<=a²+1
所以a=-1
a>1/3，2<=x<=3a+1
则有2a<=2且3a+1<=a²+1
这个不鞥同时成立
所以a=1
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