Question

一个等腰直角三角形,两条直角边的和是9.2厘米,它的面积是？

Answer 1

由题意得

∵AB⊥AC,AB=AC,AB+AC=9.2(cm)
∴AB=AC=9.2×1/2=4.6(cm)

则S△ABC=1/2×AB×AC=1/2×4.6×4.6=1/2×4.6²=1/2×21.16=10.58(cm²)
因此,△ABC的面积是10.58cm².,3,