指数运算 化简 10
1个回答
展开全部
(a^4/3-8a^1/3b)/(4b^2/3+2³√ab+a^2/3)÷[a^(-2/3)-2³√b/a]
=(a^4/3-8a^1/3b)/(4b^2/3+2a^1/3b^1/3+a^2/3)÷[a^(-2/3)-2³√b/a]
=a^1/3(a-8b)/(4b^2/3+2a^1/3b^1/3+a^2/3)÷[a^(-2/3)-2³√b/a]
=a^1/3(a^1/3-2b^1/3)(a^2/3+2a^1/3b^1/3+4b^2/3)/(4b^2/3+2a^1/3b^1/3+a^2/3)÷[a^(-2/3)-2³√b/a]
=a^1/3(a^1/3-2b^1/3)÷[a^(-2/3)-2a^(-1)b^1/3]
=a^1/3(a^1/3-2b^1/3)÷{a^(-1)[a^1/3-2b^1/3]}
=a^1/3÷a^(-1)
=a^(1/3+1)
=a^4/3
√(a*³√a^2)/[5√√(a*³√a)]
=√(a*a^2/3)/[5√√(a*a^1/3)]
=√(a^5/3)/[5√√(a^4/3)]
=a^(5/3*1/2)/[5√a^(4/3*1/2)]
=a^(5/6)/[5√a^(2/3)]
=a^(5/6)/a^(2/3*1/5)
=a^(5/6)/a^(2/15)
=a^(5/6-2/15)
=a^(25/30-4/30)
=a^(21/30)
=a^7/10
=(a^4/3-8a^1/3b)/(4b^2/3+2a^1/3b^1/3+a^2/3)÷[a^(-2/3)-2³√b/a]
=a^1/3(a-8b)/(4b^2/3+2a^1/3b^1/3+a^2/3)÷[a^(-2/3)-2³√b/a]
=a^1/3(a^1/3-2b^1/3)(a^2/3+2a^1/3b^1/3+4b^2/3)/(4b^2/3+2a^1/3b^1/3+a^2/3)÷[a^(-2/3)-2³√b/a]
=a^1/3(a^1/3-2b^1/3)÷[a^(-2/3)-2a^(-1)b^1/3]
=a^1/3(a^1/3-2b^1/3)÷{a^(-1)[a^1/3-2b^1/3]}
=a^1/3÷a^(-1)
=a^(1/3+1)
=a^4/3
√(a*³√a^2)/[5√√(a*³√a)]
=√(a*a^2/3)/[5√√(a*a^1/3)]
=√(a^5/3)/[5√√(a^4/3)]
=a^(5/3*1/2)/[5√a^(4/3*1/2)]
=a^(5/6)/[5√a^(2/3)]
=a^(5/6)/a^(2/3*1/5)
=a^(5/6)/a^(2/15)
=a^(5/6-2/15)
=a^(25/30-4/30)
=a^(21/30)
=a^7/10
本回答由网友推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
