Question

求这个方程是怎么解出来的。求过程讲解

t(t平方-3）=2
t=-1或2
初中刚毕业。。。希望有一个可以看的懂的解释

Answer 1

t(t平方-3）=2,

t^3-3t-2=0,
t^3-t-2t-2=0,
t(t^2-1)-2(t+1)=0,
t(t-1)(t+1)-2(t+1)=0,
(t+1)(t^2-t-2)=0,
(t+1)(t-2)(t+1)=0,
(t+1)^2 *(t-2)=0,
得(t+1)^2 =0或者t-2=0,
解得t=-1（二重根）或2。

Answer 2

t^3-2t^2+2t^2-4t+t-2=0

(t-2)(t^2+2t+1)=0

(t-2)(t+1)^2=0

t=-1或2

3次方一般3个解 根据最容易猜的解 将次

Answer 3

t*(t^2-3)=2
t^3-t*3-2=0
(t-2)*(t+1)^2=0
所以t=-1或t=2

Answer 4

t(t平方-3
）=2,
t^3-3t-2=0,
t^3-t-2t-2=0,
t(t^2-1)-2(t+1)=0,
t(t-1)(t+1)-2(t+1)=0,
(t+1)(t^2-t-2)=0,
(t+1)(t-2)(t+1)=0,
(t+1)^2 *(t-2)=0,
得(t+1)^2 =0或者t-2=0,
解得t=-1或2。