Question

化简:sin(2π-α)+cos(3π-α)/sin(3π/2-α)+sin(-α)

过程~谢谢

Answer 1

sin(2π-α)+cos(3π-α)/sin(3π/2-α)+sin(-α)

=(-sinα-cosα)/(-cosα-sinα)
=1

Answer 2

原式=(-sinα-cosα)/(-cosα-sinα)
=1