Question

请列出用2、5、8、0这四个数字组成的所有四位数（数字可以重复使用）

急用！
补充一下，0也可以做第一个数字，我电脑的密码忘了，只记得好像有这四个数字组成，万分感谢

Answer 1

共有：3×4×4×4=192种
2000,2002,2005,2008,2020,2022,2025,2028,2050,2052,2055,2058,2080,2082,2085,2088,
2200,2202,2205,2208,2220,2222,2225,2228,2250,2252,2255,2258,2280,2282,2285,2288,
2500,2502,2505,2508,2520,2522,2525,2528,2550,2552,2555,2558,2580,2582,2585,2588,
2800,2802,2805,2808,2820,2822,2825,2828,2850,2852,2855,2858,2880,2882,2885,2888,
5000,5002,5005,5008,5020,5022,5025,5028,5050,5052,5055,5058,5080,5082,5085,5088,
5200,5202,5205,5208,5220,5222,5225,5228,5250,5252,5255,5258,5280,5282,5285,5288,
5500,5502,5505,5508,5520,5522,5525,5528,5550,5552,5555,5558,5580,5582,5585,5588,
5800,5802,5805,5808,5820,5822,5825,5828,5850,5852,5855,5858,5880,5882,5885,5888,
8000,8002,8005,8008,8020,8022,8025,8028,8050,8052,8055,8058,8080,8082,8085,8088,
8200,8202,8205,8208,8220,8222,8225,8228,8250,8252,8255,8258,8280,8282,8285,8288,
8500,8502,8505,8508,8520,8522,8525,8528,8550,8552,8555,8558,8580,8582,8585,8588,
8800,8802,8805,8808,8820,8822,8825,8828,8850,8852,8855,8858,8880,8882,8885,8888,

追问

万分感谢！请问可以把0打头的也列出来吗？

追答

共有：4×4×4×4=256种
0做开头的数字有：
0000,0002,0005,0008,0020,0022,0025,0028,0050,0052,0055,0058,0080,0082,0085,0088,
0200,0202,0205,0208,0220,0222,0225,0228,0250,0252,0255,0258,0280,0282,0285,0288,
0500,0502,0505,0508,0520,0522,0525,0528,0550,0552,0555,0558,0580,0582,0585,0588,
0800,0802,0805,0808,0820,0822,0825,0828,0850,0852,0855,0858,0880,0882,0885,0888
只要找到规律，做起来很简单。祝你开心！

Answer 2

2580 2850 2805 2085 2058 2508 0258 0285 0528 0582 0825 0852 5028 5082 5208 5280 5802 5820 8025 8052 8250 8205 8502 8520 8888 5555 2222 0000 。。。。。。。太多了 ，一共有192种

Answer 3

首位可选2、5、8，其余每位都可选4个，总数3*4*4*4=192
你让我都列出来好像太多了吧

Answer 4

192