把下列各式分解因式
(1)3p平方(a-x)-2p²(x-a)(2)6m(p²-q)^三次方+4n(q-p²)²(3)a(x+y)+b(x+y)-c(...
(1) 3p平方(a-x)-2p²(x-a)
(2) 6m(p²-q)^三次方 + 4n ( q-p²)²
(3) a (x+y) +b (x+y) -c (x+y)
(4) 3a²b(2x-y)-6ab² (y-2x) 展开
(2) 6m(p²-q)^三次方 + 4n ( q-p²)²
(3) a (x+y) +b (x+y) -c (x+y)
(4) 3a²b(2x-y)-6ab² (y-2x) 展开
1个回答
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3p^2(a-x)-2p^2(x-a)
=3p^2(a-x)+2p^2(a-x)
=(a-x)(3p^2+2p^2)
=5p^2(a-x)
6m(p^2-q)^3+4n(q-p^2)^2
=6m(p^2-q)^3+4n(p^2-q)^2
=2(p^2-q)^2[3m(p^2-q)+2n]
=2(p^2-q)^2(3mp^2-3mq+2n)
a(x+y)+b(x+y)-c(x+y)=(x+y)(a+b-c)
3a^2b(2x-y)-6ab^2(y-2x)
=3a^2b(2x-y)+6ab^2(2x-y)
=3ab(2x-y)(a+2b)
=3p^2(a-x)+2p^2(a-x)
=(a-x)(3p^2+2p^2)
=5p^2(a-x)
6m(p^2-q)^3+4n(q-p^2)^2
=6m(p^2-q)^3+4n(p^2-q)^2
=2(p^2-q)^2[3m(p^2-q)+2n]
=2(p^2-q)^2(3mp^2-3mq+2n)
a(x+y)+b(x+y)-c(x+y)=(x+y)(a+b-c)
3a^2b(2x-y)-6ab^2(y-2x)
=3a^2b(2x-y)+6ab^2(2x-y)
=3ab(2x-y)(a+2b)
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