Question

4-（x²-4x+2）²、-9（m-n）+（m+n）²、x四次方-2x²+1 因式分解怎么写急用！谢谢

Answer 1

4-（x²-4x+2）²
=(2+x²-4x+2)(2-x²+4x-2)
=(x²-4x+4)(-x²+4x)
=x(x-2)²(4-x)

-9（m-n）²+（m+n）²
=（m+n）²-9（m-n）²
=(m+n+3m-3n)(m+n-3m+3n)
=(4m-2n)(4n-2m)
=4(2m-n)(2n-m)

x四次方-2x²+1
=(x²-1)²
=(x+1)²(x-1)²

Answer 2

4-（x²-4x+2）²
=(2+x^2-4x+2)(2-x^2+4x-2)
=(x-2)^2(x^2+4x)
=x(x+4)(x-2)^2

-9（m-n)^2+（m+n）² 题目是这样的吧?
=(m+n)^2-(3m-3n)^2
=(m+n+3m-3n)(m+n-3m+3n)
=(4m-2n)(4n-2m)
=4(2m-n)(2n-m)

x四次方-2x²+1

=(X^2-1)^2
=[(x-1)(x+1)]^2
=(x-1)^2(x+1)^2