Question

计算：a^2-1/a^2+2a+1除a^2-a/a+1

Answer 1

解：
原式=[(a²-1)/(a²+2a+1)]÷[(a²-a)/(a+1)]
=[(a+1)(a-1)/(a+1)²]÷[a(a-1)/(a+1)]
=[(a-1)/(a+1)]×{ (a+1)/[a(a-1)] }
=1/a

Answer 2

你确定中间是·除·而不是·除以·两个差别很大
如果是·除·答案如下
解原式=[(a²-a)/(a+1)]÷[(a²-1)/(a²+2a+1)]=[a(a-1)/(a+1)]÷[(a+1)(a-1)/(a+1)²]=a
如果是·除以·答案如下

解原式=[(a²-1)/(a²+2a+1)]÷[(a²-a)/(a+1)]
=[(a+1)(a-1)/(a+1)²]÷[a(a-1)/(a+1)]
=[(a-1)/(a+1)]×{ (a+1)/[a(a-1)] }
=1/a