怎么化简
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原式=[(x√x+x√y)/(xy-y²)]-[(x+√xy+y)/(x√x-y√y)]
={ x(√x+√y)/[y(x-y)] }-[(x+√xy+y)/(√x³-√y³)]
={ x(√x+√y)/[y(x-y)] } - { (x+√xy+y)/[(√x-√y)(x+√xy+y)] }
={ x(√x+√y)/[y(x-y)] } - [1/(√x-√y)]
={ x(√x+√y)/[y(x-y)] } - { y(√x+√y)/[y(√x+√y)(√x-√y)] }
={ x(√x+√y)/[y(x-y)] } - { y(√x+√y)/[y(x-y)] }
=[x(√x+√y)-y(√x+√y)]/[y(x-y)]
=(√x+√y)(x-y)/[y(x-y)]
=(√x+√y)/y
={ x(√x+√y)/[y(x-y)] }-[(x+√xy+y)/(√x³-√y³)]
={ x(√x+√y)/[y(x-y)] } - { (x+√xy+y)/[(√x-√y)(x+√xy+y)] }
={ x(√x+√y)/[y(x-y)] } - [1/(√x-√y)]
={ x(√x+√y)/[y(x-y)] } - { y(√x+√y)/[y(√x+√y)(√x-√y)] }
={ x(√x+√y)/[y(x-y)] } - { y(√x+√y)/[y(x-y)] }
=[x(√x+√y)-y(√x+√y)]/[y(x-y)]
=(√x+√y)(x-y)/[y(x-y)]
=(√x+√y)/y
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