Question

用公式法解1.-½x²－3x＋2=0 2. 2x²－2√2x－3=0

利用提公因式解： 1.x²=4x 2. ﹙x-2﹚²+2x(x-2)=0 3.(2x-1)²-4x+2=0
利用平方差公式解： 1.y²-(2y-1)²=0
2.（x-1)²=4(x+2)²

Answer 1

-1/2x^2-3x+2=0
x^2+6x-4=0
x=(-6±2√13)/2
x1=-3+√13
x2=-3-√13

2x^2-2√2x-3=0
x=(2√2±4√2)/4
x1=(3√2)/2
x2=-(√2)/2

x^2=4x
x^2-4x=0
x(x-4)=0
x1=0 x2=4

(x-2)^2+2x(x-2)=0
(x-2)(x-2+2x)=0
x1=2 x2=2/3

(2x-1)^2-4x+2=0
(2x-1)^2-2(2x-1)=0
(2x-1)(2x-3)=0
x1=1/2 x2=3/2

y^2-(2y-1)^2=0
(y+2y-1)(y-2y+1)=0
(3y-1)(1-y)=0
y1=1/3 y2=1

(x-1)²=4(x+2)²
(x-1)²-[2(x+2)]²=0
(x-1+2x+4)(x-1-2x-4)=0
(3x+3)(-x-5)=0
(x+1)(x+5)=0
x1=-1 x2=-5

Answer 2

e

Answer 3

-1/2x^2-3x+2=0
x^2+6x-4=0
x=(-6±2√13)/2
x1=-3+√13
x2=-3-√13

2x^2-2√2x-3=0
x=(2√2±4√2)/4
x1=(3√2)/2
x2=-(√2)/2

x^2=4x
x^2-4x=0
x(x-4)=0
x1=0 x2=4

(x-2)^2+2x(x-2)=0
(x-2)(x-2+2x)=0
x1=2 x2=2/3

(2x-1)^2-4x+2=0
(2x-1)^2-2(2x-1)=0
(2x-1)(2x-3)=0
x1=1/2 x2=3/2

y^2-(2y-1)^2=0
(y+2y-1)(y-2y+1)=0
(3y-1)(1-y)=0
y1=1/3 y2=1

(x-1)²=4(x+2)²
(x-1)²-[2(x+2)]²=0
(x-1+2x+4)(x-1-2x-4)=0
(3x+3)(-x-5)=0
(x+1)(x+5)=0
x1=-1 x2=-5
明白了吗