c语言,下面程序运行的结果是什么?
fun(char*w,intn){chart,*s1,*s2;s1=w;s2=w+n-1;while(s1<s2){t=*s1++;*s1=*s2--;*s2=t;}}m...
fun ( char *w , int n )
{ char t , * s1 , * s2 ;
s1 = w ; s2 = w+n-1 ;
while (s1 < s2 ) { t = * s1 ++ ; * s1 = *s2 - - ; *s2 = t ; }
}
main ()
{ char *p ;
p ="1234567" ;
fun (p , strlen(p));
puts(p);
}
提问:
1、上面程序运行的结果是什么?
2、求详细解答过程 展开
{ char t , * s1 , * s2 ;
s1 = w ; s2 = w+n-1 ;
while (s1 < s2 ) { t = * s1 ++ ; * s1 = *s2 - - ; *s2 = t ; }
}
main ()
{ char *p ;
p ="1234567" ;
fun (p , strlen(p));
puts(p);
}
提问:
1、上面程序运行的结果是什么?
2、求详细解答过程 展开
2个回答
展开全部
最后输出“1711717”
过程:
进入fun后s1指向字符‘1’,s2指向字符'7'
t = ’1‘,s1指向’2‘,( w = "1234567")
w = "1734567",s2指向’6‘
w = "1734517"
t = 7,s1指向’3‘,(w = "1734517")
w = "1714517",s2指向’5‘
w = "1714717"
t = '1',s1指向’4‘, (w = "1714717")
w = "1717717",s2指向左数第2个’7‘
w = "1711717"
s1 == s2, break
函数fun返回,输出1711717
过程:
进入fun后s1指向字符‘1’,s2指向字符'7'
t = ’1‘,s1指向’2‘,( w = "1234567")
w = "1734567",s2指向’6‘
w = "1734517"
t = 7,s1指向’3‘,(w = "1734517")
w = "1714517",s2指向’5‘
w = "1714717"
t = '1',s1指向’4‘, (w = "1714717")
w = "1717717",s2指向左数第2个’7‘
w = "1711717"
s1 == s2, break
函数fun返回,输出1711717
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