1/1×3+1/3×5+1/5×7+1/7×9+1/9×11 简便算法
1个回答
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1/1×3+1/3×5+1/5×7+1/7×9+1/9×11
=(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11)÷2
=(1-1/11)÷2
=10/11÷2
=5/11
=(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11)÷2
=(1-1/11)÷2
=10/11÷2
=5/11
追问
我没看明白啊。可以说的详细点么?
追答
1/1×3=(1-1/3)÷2
1/3×5=(1/3-1/5)÷2
1/5×7=(1/5-1/7)÷2
1/7×9=(1/7-1/9)÷2
1/9×11=(1/9-1/11)÷2
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