Question

用十字相乘法把下列格式分解因式，急用！！

1、x²(2a+b)x+2ab
2、x²+mx-2m²
3、x²-(m²+1)x+m²
4、x²+(m-1)x-m
5、x²+(a-2)x-2a
6、x²-(m+2)x+m+1
7、x²+(k-2)x+k-3
8、x²-(m-3)x+m-4
9、x²-4ax+3a²+2a-1
10、x平方-(2m-1)x+m²-m
11、x²-(2m+1)x+m²+m-2

Answer 1

1、x²+(2a+b)x+2ab=(x+2a)(x+b)
2、x²+mx-2m²=(x+2m)(x-m)
3、x²-(m²+1)x+m²=(x²-m²)(x-1)
4、x²+(m-1)x-m=(x+m)(x-1)
5、x²+(a-2)x-2a=(x+a)(x-2)
6、x²-(m+2)x+m+1=(x-1)(x-m-1)
7、x²+(k-2)x+k-3=(x+1)(x+k-3)
8、x²-(m-3)x+m-4=(x-1)(x-m+4)
9、x²-4ax+3a²+2a-1=x²-4ax+(a+1)(3a-1)=(x-a-1)(x-3a+1)
10、x平方-(2m-1)x+m²-m=(x-m)(x-m+1)11、x²-(2m+1)x+m²+m-2=x²-(2m+1)x+(m+2)(m-1)=(x-m-2)(x-m+1)

Answer 2

1、x²+(2a+b)x+2ab=(x+2a)(x+b)
2、x²+mx-2m²=(x+2m)(x-m)
3、x²-(m²+1)x+m²=(x²-m²)(x-1)
4、x²+(m-1)x-m=(x+m)(x-1)
5、x²+(a-2)x-2a=(x+a)(x-2)
6、x²-(m+2)x+m+1=(x-1)(x-m-1)
7、x²+(k-2)x+k-3=(x+1)(x+k-3)
8、x²-(m-3)x+m-4=(x-1)(x-m+4)
9、x²-4ax+3a²+2a-1=x²-4ax+(a+1)(3a-1)=(x-a-1)(x-3a+1)
10、x平方-(2m-1)x+m²-m=(x-m)(x-m+1)11、x²-(2m+1)x+m²+m-2=x²-(2m+1)x+(m+2)(m-1)=(x-m-2)(x-m+1)
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