
已知关于x的方程1/4X2+﹙M-3﹚X+M2=0
2个回答
展开全部
1/4x^2+(m-3)x+m^2=0
x^2+4(m-3)x+4m^2=0
16(m-3)^2-16m^2=16m^2-96m+16*9-16m^2=16*9-96m=16(9-6m)
x=(-4(m-3))+-4(9-6m)^1/2)/2
x=-2(m-3)+-2(9-6m)^1/2
9-6m>=0
6m<=9
m<=3/2
有实数根
x^2+4(m-3)x+4m^2=0
16(m-3)^2-16m^2=16m^2-96m+16*9-16m^2=16*9-96m=16(9-6m)
x=(-4(m-3))+-4(9-6m)^1/2)/2
x=-2(m-3)+-2(9-6m)^1/2
9-6m>=0
6m<=9
m<=3/2
有实数根
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