Question

高一数学解方程和不等式，帮忙下

x³-x²-2x+2=0
x²+y²-2x+4y+5=0
|2x+1|>2

Answer 1

x³-x²-2x+2=0
x²(x-1)-2(x-1)=0
(x²-2)(x-1)=0
x²-2=0或x-1=0
x=±√2或x=1
x²+y²-2x+4y+5=0
(x-1)²+(y+2)²=0
x-1=0
y+2=0
x=1
y=-2
|2x+1|>2
2x+1>2或2x+1<-2
x>1/2或x<-3/2

Answer 2

1：x3-x2-2x+2=0
x2(x-1)-2(x-1)=0
(x2-2)(x-1)=0
x2=2或x=1
x=根号2或x=-根号2或x=1；
2:x2+y2-2x+4y+5=0
(x2-2x+1)+(y2+4y+4)=0
(x-1)2+(y+2)2=0
x-1=0,y+2=0
x=1,y=-2;
3：|2x+1|>2
2x+1>2或2x+1<-2
x>1/2或x<-3/2;

Answer 3

1. X2(X-1)-2(X-1)=0

    （X2-2）（x-1)=0

      x=正负根号2，x=1

2.   

3.   2x+1>2或2x+1<-2

      所以x>1/2 ,x<-3/2