x的二次方(x+1)-y(xy+x) 分解因式
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x^2(x+1)-y(xy+x)
=x^2(x+1)-xy(y+1)
=x((x(x+1)-y(y+1))
=x(x^2+x-y^2-y)
=x((x-y)(x+y)+(x-y))
=x(x-y)(x+y+1)
=x^2(x+1)-xy(y+1)
=x((x(x+1)-y(y+1))
=x(x^2+x-y^2-y)
=x((x-y)(x+y)+(x-y))
=x(x-y)(x+y+1)
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解：原式=x²(x+1) -xy(y+1)
=x[x(x+1)-y(y+1)]
=x{x²+x-y²-y]
=x[(x²-y²)+(x-y)]
=x[(x+y)(x-y)+(x-y)]
=x(x-y)(x+y+1)
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=x[x(x+1)-y(y+1)]
=x{x²+x-y²-y]
=x[(x²-y²)+(x-y)]
=x[(x+y)(x-y)+(x-y)]
=x(x-y)(x+y+1)
【俊狼猎英】团队为您解答
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