Question

化简 x2+3x+9/x2-27 + 6x/9x-x2 -x-1/6+2x

中间有空格的表示是不同的多项式，但这是一道题，请给详细的步骤

Answer 1

原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)
=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)
=(2x+6-12-x²+4x-3)/2(x+3)(x-3)
=-(x²-6x+9)/2(x+3)(x-3)
=-(x-3)²/2(x+3)(x-3)
=(3-x)/(2x+6)