Question

(解方程36χ²-1=0 (2)4χ²=81 (3)(χ+5)²=25(4)χ²+2χ+1=4 要过程

(1)36χ²-1=0 (2)4χ²=81 (3)(χ+5)²=25(4)χ²+2χ+1=4 急啊，，在线

Answer 1

(1)36χ²-1=0
（6X+1）（6X-1）=0
6X+1=0或6X-1=0
X1= -1/6或X2=1/6

(2)4χ²=81
4X²-81=0
(2X+9)(2X-9)=0
2X+9=0或2X-9=0
X1= -4.5或X2=4.5

(3)(χ+5)²=25
X+5= -5或X+5=5
X1= -10或X2=0

(4)χ²+2χ+1=4
X²+2X+1-4=0
X²+2X-3=0
X+3=0或X-1=0
X1= -3或X2=1

Answer 2

(1)36χ²-1=0
x²=1/36
x=-1/6,x=1/6

(2)4χ²=81
x²=81/4
x=-9/2,x=9/2

(3)(χ+5)²=25
x+5=-5,x+5=5
x=-10,x=0

(4)χ²+2χ+1=4

(x+1)²=4
x+1=-2,x+1=2
x=-3,x=1

Answer 3

1. x=±1/6
2. x=±9/2
3. x=0或x=-10
4. (x+1)^2=4
x=1或x=-3