Question

java求把数组‘12345’改为‘54321’.

Answer 1

public class Demo1 {
public static int[] a={1,2,3,4,5};
public static void main(String[] args) {
int[] b=new int[5];
for (int i = 0; i < b.length; i++) {
b[i]=a[b.length-1-i];
}
for (int i = 0; i < b.length; i++) {
System.out.println(b[i]);
}
}
}

Answer 2

public class SZDZ {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub

int[]array={1,2,3,4,5};
int[]iarray=new int[5];
for(int a=0;a<5;a++){
iarray[a]=array[array.length-a-1];
System.out.print(iarray[a]);

}

Answer 3

虽然已经有正确答案了，我想给你一个更高效的算法,运行更快，内存占用更小：
public class Demo {
public static int[] a={1,2,3,4,5};
public static void main(String[] args) {
int length = a.length;
int len = a.length/2;
int temp;
for (int i = 0; i<len; i++) {
temp = a[i];
a[i] = a[length-i];
a[length-i] = temp ;

}
for (int i = 0; i < a.length; i++) {
System.out.println(a[i]);
}
}
}

Answer 4

public class Demo10{
public static void main(String[] args){
int[] a = {1,2,3,4};
int temp = 0;
for(int i=1;i<a.length;i++){

for(int j=0;j<a.length;j++){
if(a[i] > a[j]){
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.println();
for(int i=0;i<a.length;i++){
System.out.print(a[i]+"\t");
}
}
}

Answer 5

数组倒置。。。。。或者说数组翻转。