Question

解一元二次方程:用公式法解关于x的方程x2-(2m+1)x+m2+m等于0,拜托,帮帮忙

Answer 1

解：∵a=1, b=-(2m+1), c=m²+m
b²-4ac=[-(2m+1)]²-4×1×(m²+m)
=4m²+4m+1-4m²-4m
=1
∴x={-[-(2m+1)]±√1}/2
=(2m+1±1)/2
x1=(2m+1+1)/2=m+1
x2=(2m+1-1)/2=m

Answer 2

△=（2m+1）^2-4（m^2+m）=4m^2+4m+1-4m^2-4m=1
X=(2m+1±√1)/2=（2m）/2 或（2m+2）/2
∴X=m 或 m+1

Answer 3

解：∵a=1, b=-(2m+1), c=m²+m
b²-4ac=[-(2m+1)]²-4×1×(m²+m)
=4m²+4m+1-4m²-4m
=1
∴x={-[-(2m+1)]±√1}/2
=(2m+1±1)/2
x1=(2m+1+1)/2=m+1
x2=(2m+1-1)/2=m

Answer 4

x=m或x=m+1