小学奥数题,麻烦给个简单方法,谢谢!12345x12346-12344X12343 这道题的奥数方法?????
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换元法:设a=12345,那么12346=a+1,12344=a-1,12343=a-2
原式=a*(a+1)-(a-1)*(a-2)=a²+a-a²+3a-2
=4a-2
=4*12345-2
=49380-2
=49378
原式=a*(a+1)-(a-1)*(a-2)=a²+a-a²+3a-2
=4a-2
=4*12345-2
=49380-2
=49378
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你好, John200302:
12345×12346-12344×12343
=12345×12346-(12345-1)×12343
=12345×12346-12345×12343+12343
=12345×(12346-12343)+12345-2
=12345×(12346-12343+1)-2
=12345×4-2
=49380-2
=49378
12345×12346-12344×12343
=12345×12346-(12345-1)×12343
=12345×12346-12345×12343+12343
=12345×(12346-12343)+12345-2
=12345×(12346-12343+1)-2
=12345×4-2
=49380-2
=49378
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12345的平方+12345-12344的平方+12344=12345*2+12344*2
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12345×12346-12344×12343
=12345×12346-(12345-1)×12343
=12345×12346-12345×12343+12343
=12345×(12346-12343)+12345-2
=12345×(12346-12343+1)-2
=12345×4-2
=49380-2
=49378
=12345×12346-(12345-1)×12343
=12345×12346-12345×12343+12343
=12345×(12346-12343)+12345-2
=12345×(12346-12343+1)-2
=12345×4-2
=49380-2
=49378
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=12345*(12345+1)-(12345-1)*(12345-2)
=12345²+12345-(12345²-3*12345+2)
=12345²+12345-12345²+3*12345-2
=4*12345-2
=49378
=12345²+12345-(12345²-3*12345+2)
=12345²+12345-12345²+3*12345-2
=4*12345-2
=49378
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