Question

请仔细回答下面的奥数题，用简便计算，要有过程！

(1)47/48*37= (2)7/12*25= (3)1994*1992/1993= (4)1/5*27+3/5*41

Answer 1

(1)47/48*37
=（1-1/48）*37
=1*37-1/48*37
=37-37/48
=36又11/48

(2)7/12*25
=7/12*（24+1）
=7/12*24+7/12*1
=14+7/12
=14又7/12

(3)1994*1992/1993
=（1993+1）*1992/1993
=1993*1992/1993+1*1992/1993
=1992+1992/1993
=1992又1992/1993

(4)1/5*27+3/5*41
=1/5*27+1/5*（3*41）
=1/5*（27+123）
=1/5*150
=30

Answer 2

(1－1/48)*37=37-37/48=36又11/48
7/12*(24+1)=14+7/12=14又7/12
(1993+1)*1992/1993=1992+1992/1993=1992又1992/1993
3/5*9+3/5*41=3/5*50=30