求极限lim(x趋近于无穷)(x^2+x根号(x^2+2))
2个回答
展开全部
中间是"-"吧?lim(x→∞) x²-x√(x²+2)
分子有理化
lim(x→∞) x²-x√(x²+2)
=lim(x→∞) [x²+x√(x²+2)][x²-x√(x²+2)]/[x²+x√(x²+2)]
=lim(x→∞) (x^4-x^4-2x²)/[x²+x√(x²+2)]
=lim(x→∞) (-2x²)/[x²+x√(x²+2)]
=lim(x→∞) (-2)/[1+√(1+2/x²)]
=-1
====================
如果确实是"+", lim(x→∞) x²+x√(x²+2)当然趋于∞
分子有理化
lim(x→∞) x²-x√(x²+2)
=lim(x→∞) [x²+x√(x²+2)][x²-x√(x²+2)]/[x²+x√(x²+2)]
=lim(x→∞) (x^4-x^4-2x²)/[x²+x√(x²+2)]
=lim(x→∞) (-2x²)/[x²+x√(x²+2)]
=lim(x→∞) (-2)/[1+√(1+2/x²)]
=-1
====================
如果确实是"+", lim(x→∞) x²+x√(x²+2)当然趋于∞
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询