一元二次方程3x^2+2x-2=3(x+__)^2+(__)
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先都提取3
则3x^2+2x-2
=3(x²+2/3x-2/3)
=3(x²+2/3x+1/9-1/9-2/3)
=3(x²+2/3x+1/9)-3(1/9+2/3)
=3(x+1/3)²-7/3
则3x^2+2x-2
=3(x²+2/3x-2/3)
=3(x²+2/3x+1/9-1/9-2/3)
=3(x²+2/3x+1/9)-3(1/9+2/3)
=3(x+1/3)²-7/3
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