Question

java中，tostring如何重写，显示数据，请补充

如下程序缺少toString函数没有填写，请补充，使现在运行为数据，不是地址的乱码
import java.util.*;
public class poke implements Comparable<poke>{
public static void main(String[] args) {
// TODO 自动生成方法存根
List<poke> arraylist = new ArrayList<poke>();
int i,j,k;
String[] huase ={"Hongtao","Fangkuai","Heitao","Meihua"};
String[] num = {"1","2","3","4","5","6","7","8","9","10","J","Q","K"};
for(i=1; i<3; i++){
for(j=0; j<4; j++){
for(k=0; k<13; k++)
arraylist.add(new poke(num[k],huase[j],i));
}
}
System.out.println(arraylist);
}
public String Number;
public String Huase;
public int PaiID;
public poke(String number,String huase,int paiID){
this.Number = number;
this.Huase = huase;
this.PaiID = paiID;
}

public String getHuase() {
return Huase;
}
public void setHuase(String huase) {
Huase = huase;
}
public String getNumber() {
return Number;
}
public void setNumber(String number) {
Number = number;
}
public int getPaiID() {
return PaiID;
}
public void setPaiID(int paiID) {
PaiID = paiID;
}

public int compareTo(poke p) {
// TODO 自动生成方法存根
return 0;
}
public String toSting(){
return Huase+Number;
}

}

Answer 1

1. 在eclipse中按住快捷键alt+shif+s 

2. 选择Generate toString();自动生成

public String toString() {
		return "poke [Number=" + Number + ", Huase=" + Huase + ", PaiID="
				+ PaiID + "]";
	}

Answer 2

List<poke> arraylist = new ArrayList<poke>();

System.out.println(arraylist);

你要重写ArrayList类的方法不过直接改好像不行，你写个子类继承ArrayList
再重写下toString方法

追问

怎么样修改，可以的话，直接修改，把代码发过来吧。。。谢谢

追答

1. 写个类继承ArrayList , 只重写toString方法

Answer 3

public String toString(){
return a+b+c://所需要的串
}

Answer 4

就