Question

c语言试题 输入一个三位正整数，将该数的百位，十位，和个位的数分三行输出 ，并输出三位数的和

输入一个三位正整数，将该数的百位，十位，和个位的数分三行输出 ，并输出三位数的和

例：输入：357
输出：
3
5
7
3+5+7=12

怎么做啊 求解

Answer 1

只是三位数的话，下面的代码就可以了！
#include<stdio.h>
int main()
{
int n;
int a,b,c;
scanf("%d",&n);
a=n%10;
b=n/10%10;
c=n/100;
printf("%d\n",c);
printf("%d\n",b);
printf("%d\n",a);
printf("%d+%d+%d=%d\n",c,b,a,a+b+c);
}

Answer 2

输出个、十、百位的数值并求和的代码就：

#include<stdio.h>

int main()

{

int num;

int a,b,c;

scanf("%d",&num);

a = num/100;

b = (num%100)/10;

c = num%10;

printf("a= %d,b = %d,c= %d\n",a,b,c);

return 0;

}

Answer 3

#include <stdio.h>
int main()
{
int n,count,digit[10],i,sum;
scanf("%d",&n);
for(i=0;n;++i)
{
digit[i]=n%10;
n/=10;
printf("%d\n",digit[i]);
}
for(count=i,sum=i=0;i<count;++i)
{
sum+=digit[i];
printf("%d",digit[i]);
if(i==count-1)
{
printf("=");
}
else
{
printf("+");
}
}
printf("%d\n",sum);
return 0;
}

Answer 4

#include <stdio.h>

int main( void ){
int a=0;
int x,y,z;
while( EOF == scanf("%d",&a) || a > 999 || a < 100 )
printf("input integer more than 100 and less than 1000:");
x = a/100;
y = a/10%10;
z = a%10;
printf("%d\n%d\n%d\n",x,y,z);
printf("%d+%d+%d=%d\n",x,y,z,x+y+z);

return 0;

}