Question

哪位单片机高手给我看看这个程序到底哪错了，初学者，纠结呀要求只显示有效位，为什么只显示第一个呢

//2012年10月4日11:42:31 简易秒表
# include <reg52.h>
typedef unsigned char uint8;
typedef unsigned int uint16;
typedef unsigned long uint32;
sbit LED = P0^0;
sbit ENLED = P1^4;
sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
code uint8 number[] = {0xc0,0xf9,0xa4,0xb0,
0x99,0x92,0x82,0xf8,
0x80,0x90,0x88,0x83,
0xa7,0xa1,0x86,0x8e};//加分号语句
uint8 a[6];
uint16 counter = 0;
void timer1_init()
{
TMOD |= 0X10;//与和或符号靠近等于号
TMOD &= 0XDF;
TH1 = 0XFC;
TL1 = 0X67;
TR1 = 1;

}
void int1_init()
{
ET1 = 1;
EA = 1;

}
refresh()
{
static uint32 sec=0;

if(sec<10)
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
if(sec>=10&&sec<100)
{
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
}
if(sec>=100&&sec<1000)
{
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
ADDR0 = 0; ADDR1 = 1; ADDR2 = 0; P0 = number[a[2]];
}
if(sec>=1000&&sec<10000)
{
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
ADDR0 = 0; ADDR1 = 1; ADDR2 = 0; P0 = number[a[2]];
ADDR0 = 1; ADDR1 = 1; ADDR2 = 0; P0 = number[a[3]];
}
if(sec>=10000&&sec<100000)
{

ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
ADDR0 = 0; ADDR1 = 1; ADDR2 = 0; P0 = number[a[2]];
ADDR0 = 1; ADDR1 = 1; ADDR2 = 0; P0 = number[a[3]];
ADDR0 = 0; ADDR1 = 0; ADDR2 = 1; P0 = number[a[4]];

}
if(sec>=100000)
{ ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
ADDR0 = 0; ADDR1 = 1; ADDR2 = 0; P0 = number[a[2]];
ADDR0 = 1; ADDR1 = 1; ADDR2 = 0; P0 = number[a[3]];
ADDR0 = 0; ADDR1 = 0; ADDR2 = 1; P0 = number[a[4]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 1; P0 = number[a[5]];
}

}

int main()
{
ENLED = 0;ADDR3 = 1;
timer1_init();
int1_init(); //不能加void
while(1);

}
void interrupt_timer1() interrupt 3
{
static uint32 sec = 0;
TH1 = 0XFC;
TL1 = 0X67;
counter++;
if(counter == 1000)
{
sec++;
counter = 0;
a[0] = sec%10;
a[1] = sec/10%10;
a[2] = sec/100%10;
a[3] = sec/1000%10;
a[4] = sec/10000%10;
a[5] = sec/100000%10;

}
refresh();

}
要求数码管只显示有效位，就好似到了时间他这位才亮，实现简易计时功能

Answer 1

单片机（Microcontrollers）是一种集成电路芯片，是采用超大规模集成电路技术把具有数据处理能力的中央处理器CPU、随机存储器RAM、只读存储器ROM、多种I/O口和中断系统、定时器/计数器等功能（可能还包括显示驱动电路、脉宽调制电路、模拟多路转换器、A/D转换器等电路）集成到一块硅片上构成的一个小而完善的微型计算机系统，在工业控制领域广泛应用。从上世纪80年代，由当时的4位、8位单片机，发展到现在的300M的高速单片机。

Answer 2

仅供参考：

refresh()

{
if(sec < 10) {
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
}
else if(sec < 100) {
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
}
else if(sec < 1000) {
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
ADDR0 = 0; ADDR1 = 1; ADDR2 = 0; P0 = number[a[2]];
}
else if(sec < 10000) {
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
ADDR0 = 0; ADDR1 = 1; ADDR2 = 0; P0 = number[a[2]];
ADDR0 = 1; ADDR1 = 1; ADDR2 = 0; P0 = number[a[3]];
}
else if(sec < 100000) {
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
ADDR0 = 0; ADDR1 = 1; ADDR2 = 0; P0 = number[a[2]];
ADDR0 = 1; ADDR1 = 1; ADDR2 = 0; P0 = number[a[3]];
ADDR0 = 0; ADDR1 = 0; ADDR2 = 1; P0 = number[a[4]];
}
else {
ADDR0 = 0; ADDR1 = 0; ADDR2 = 0; P0 = number[a[0]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 0; P0 = number[a[1]];
ADDR0 = 0; ADDR1 = 1; ADDR2 = 0; P0 = number[a[2]];
ADDR0 = 1; ADDR1 = 1; ADDR2 = 0; P0 = number[a[3]];
ADDR0 = 0; ADDR1 = 0; ADDR2 = 1; P0 = number[a[4]];
ADDR0 = 1; ADDR1 = 0; ADDR2 = 1; P0 = number[a[5]];
}
}

uint32 sec = 0; //该在最前面定义

Answer 3

你至少要把电路图一起发出来啊……还有你想要达到的目的……整个程序也没有注释，这样怎么帮你看……

追问

就是数码管显示的时候只要有效位，就动态显示那边搞错了，我不会改，不好意思了，

Answer 4

有一个很明显的错误, sec 应该设为全局变量,并且不要设为静态变量,改了再试试吧

Answer 5

我也是初学者不过看不等你的程序