sinπ/12-√3cosπ/12的值 要详细过程.
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sinπ/12-√3cosπ/12
=2[(1/2)*sin(π/12)-(√3/2)*cos(π/12)]
=2[sin(π/12)cos(π/3)-cos(π/12)sin(π/3)]
=2sin(π/12 - π/3)
=2sin(-π/4)
=-2sin(π/4)
=-根号2
=2[(1/2)*sin(π/12)-(√3/2)*cos(π/12)]
=2[sin(π/12)cos(π/3)-cos(π/12)sin(π/3)]
=2sin(π/12 - π/3)
=2sin(-π/4)
=-2sin(π/4)
=-根号2
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