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1、(x+2)²-25=0
[(x+2)+5][(x+2)-5]=0
(x+7)(x-3)=0
x=-7 x=3
2、x²+4x=5
x²+4x-5=0
(x+5)(x-1)=0
x=-5 x=1
3、3x²-7x+2=0
(3x-1)(x-2)=0
x=1/3 x=2
4、3(x-5)²=2(5-x)
3(x-5)²+2(x-5)=0
(x-5)[3(x-5)+2]=0
(x-5)(3x-13)=0
x=5 x=13/3
[(x+2)+5][(x+2)-5]=0
(x+7)(x-3)=0
x=-7 x=3
2、x²+4x=5
x²+4x-5=0
(x+5)(x-1)=0
x=-5 x=1
3、3x²-7x+2=0
(3x-1)(x-2)=0
x=1/3 x=2
4、3(x-5)²=2(5-x)
3(x-5)²+2(x-5)=0
(x-5)[3(x-5)+2]=0
(x-5)(3x-13)=0
x=5 x=13/3
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