Question

因式分解：11（a-b)(11分之1(b-a)³ 怎么做？

因式分解：2x³-8x=
36x-x³=
16ax²-9ay²=
-3a³b²+12ac²=
a(7x+6y)²-25az²=
3a（a+b)-27ab²=

Answer 1

11（a-b)(11分之1(b-a)³
=(a-b)(b-a)³
=-(a-b)(a-b)³
=-(a-b)^4

2x³-8x=2(x²-4)=2(x-2)(x+2)

36x-x³=x(36-x²)=x(6-x)(6+x)

16ax²-9ay²=a(16x²-9y²)=a(4x-3y)(4x+3y)

-3a³b²+12ac²=-3a(a²b²-4c²)=-3a(ab-2c)(ab+2c)

a(7x+6y)²-25az²=a[(7x+6y)²-25z²]=a(7x++6y-5z)(7x+6y+5z)

3a（a+b)²-27ab²=3a[(a+b)²-9b²]=3a(a+b-3b)(a+b+3b)=3a(a-2b)(a+4b)