
已知:x=根号3+1,y=根号3-1,求下列各式的值.
2个回答
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x=√3+1 , y=√3-1
x²+2xy+y²
=(x+y)²
=(√3+1+√3-1)²
=(2√3)²
=12
x²-y²
=(x+y)(x-y)
=(√3+1+√3-1)(√3+1-√3+1)
=2√3×2
=4√3
x²+2xy+y²
=(x+y)²
=(√3+1+√3-1)²
=(2√3)²
=12
x²-y²
=(x+y)(x-y)
=(√3+1+√3-1)(√3+1-√3+1)
=2√3×2
=4√3
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