sql内连接无法绑定由多个部分组成的标识符
SELECT*FROMjb_inf[INNER]JOINcj1_infONjb_inf.姓名=cj1_inf.姓名...
SELECT *
FROM jb_inf [INNER] JOIN cj1_inf
ON jb_inf.姓名=cj1_inf.姓名 展开
FROM jb_inf [INNER] JOIN cj1_inf
ON jb_inf.姓名=cj1_inf.姓名 展开
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