Question

解方程组(x+2)(y-1)=(x-2)(y+3)和（x-12）（y-12）=（x+12）（y-2）

Answer 1

(x+2)(y-1)=(x-2)(y+3)
xy-x+2y-2=xy+3x-2y-6
4y-4x+4=0
y=x-1 (1)

（x-12）（y-12）=（x+12）（y-2）
xy-12x-12y+144=xy-2x+12y-24
24y+10x-168=0
将(1)代入,得x=96/17,y=79/17

追问

谢谢

追答

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Answer 2

(x+2)(y-1)=(x-2)(y+3)
xy-x+2y-2=xy+3x-2y-6
4y-4x+4=0
y-x+1=0
（x-12）（y-12）=（x+12）（y-2）
xy-12x-12y+144=xy-2x+12y-24
10x+24y-168=0
5x+12y-84=0
联立求解
x=96/17 y=79/17

Answer 3

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追问

I will do it, won't trouble you.