
计算:(x+1)(x^2+1)(x^4+1)(x^8+1)
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解:
(x+1)(x^2+1)(x^4+1)(x^8+1)
=(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)/(x-1)
=(x^2-1)(x^2+1)(x^4+1)(x^8+1)/(x-1)
=(x^4-1)(x^4+1)(x^8+1)/(x-1)
=(x^8-1)(x^8+1)/(x-1)
=(x^16-1)/(x-1)
(x+1)(x^2+1)(x^4+1)(x^8+1)
=(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)/(x-1)
=(x^2-1)(x^2+1)(x^4+1)(x^8+1)/(x-1)
=(x^4-1)(x^4+1)(x^8+1)/(x-1)
=(x^8-1)(x^8+1)/(x-1)
=(x^16-1)/(x-1)

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(x+1)(x^2+1)(x^4+1)(x^8+1)
=(x+1)(x^2+1)(x^4+1)(x^8+1)
=(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)/(x-1)
=(x^2-1)(x^2+1)(x^4+1)(x^8+1)/(x-1)
=(x^4-1)(x^4+1)(x^8+1)/(x-1)
=(x^8-1)(x^8+1)/(x-1)
=(x^16-1)/(x-1)赞同2| 评论(1)
=(x+1)(x^2+1)(x^4+1)(x^8+1)
=(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)/(x-1)
=(x^2-1)(x^2+1)(x^4+1)(x^8+1)/(x-1)
=(x^4-1)(x^4+1)(x^8+1)/(x-1)
=(x^8-1)(x^8+1)/(x-1)
=(x^16-1)/(x-1)赞同2| 评论(1)
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2012-10-14
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