Question

linux shell脚本下使用for循环 输出等边三角形 过任务的 求大神指点

输出 + ++ +++ +++++ 类型的金字塔

Answer 1

#!/bin/bash
read -p "please input the longs:" long
for((i=1;i<=$long;i++))
do
for((j=$long;j>i;j--))
do
echo -n " "
done
for m in `seq 1 $i`
do
echo -n "+"
done
for((n=1;n<i;n++))
do
echo -n "+"
done
echo ""
done

long为你自己输入的边长，如果有规定长度，把$long改成数就行

Answer 2

[seesea2517 ~]$ ./a.sh 1
+

[seesea2517 ~]$ ./a.sh 2
+
+++

[seesea2517 ~]$ ./a.sh 3
+
+++
+++++

[seesea2517 ~]$ ./a.sh 6
+
+++
+++++
+++++++
+++++++++
+++++++++++

[seesea2517 ~]$ cat a.sh
#!/bin/bash

if [ -z "$1" ]
then
echo "需要参数一，表示高度。"
exit
fi

for (( i = 1; i <= $1; ++i ))
do
line=""
for (( j = $1; j >= i; --j ))
do
line="$line "
done

for (( j = 0; j < 2 * i - 1; ++j ))
do
line="$line+"
done

echo "$line"
done

Answer 3

#!/bin/sh
n=3
i=1
while [ $i -le $n ]; do
j=1
while [ $j -le $((n-i)) ] ; do
echo -n ' '
let j+=1
done

j=1
while [ $j -le $((2*i-1)) ]; do
#echo -n $j
if [ $j -eq 1 -o $j -eq $n -o $j -eq $((2*i-1)) ]; then
echo -n x
else
echo -n ' '
fi
let j+=1
done
echo
let i+=1
doneexit 0

Answer 4

题意不清