Question

100＋（X-100）/10＝200＋[X-200-100-(X-100)/10]/10

求这道题的解，要写过程，否则不给分

Answer 1

100＋（X-100）/10＝200＋[X-200-100-(X-100)/10]/10 两边乘10得1000+X-100=2000+X-200-100-(X-100)/10X+900=1700+X-(X-100)/10(X-100)/10=800X-100=8000X=7900

Answer 2

等号两边同时×10，得1000+x-100=2000+[x-300-（x-100)/10]整理得：900+X=2000+X-300得：x-100/10=800所以X=8100

Answer 3

100＋（X-100）/10＝200＋[X-200-100-(X-100)/10]/10
1000＋（X-100）＝2000＋[X-200-100-(X-100)/10]
X-100＝1000＋[(X-100)-200-(X-100)/10]
10X-1000＝10000＋[10(X-100)-2000-(X-100)]
10X-1000＝10000＋[9(X-100)-2000]
X-1000＝10000-900-2000
X＝10000-900-1000
X＝8100