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(3/2x2-5xy+y3)-【-3xy+2(1/4x2-xy)+2/3y2】,其中/x-1/+(y+2)2=0
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解:
原式=3/2x²-1/2x²-5xy+3xy+2xy+y³-2/3y²
=x²+y³-2/3y² (其中x=1,y=-2)
=1-(-2)³-2/3(-2)²
=1+9-8/3
=7+1/3
=7又1/3
原式=3/2x²-1/2x²-5xy+3xy+2xy+y³-2/3y²
=x²+y³-2/3y² (其中x=1,y=-2)
=1-(-2)³-2/3(-2)²
=1+9-8/3
=7+1/3
=7又1/3
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