Question

请帮忙解一道数学题

求X=？请写过程，谢谢！

Answer 1

换底,不过,只需换成以3为底就行了,等式左边不动,变右边.此外,n*log(a)b=log(a)b^n
掌握了上述知识,就可以解答本题了.
log(3)x=-1/log(2)3
log(3)x=-1/(log(3)3/log(3)2 (换成以3为底)
log(3)x=-log(3)2 (繁分数的运算及log( 3)3=1)
log(3)x=log(3)2^-1 (n*log(a)b=log(a)b^n)
log(3)x=log(3)(1/2) (负指数的定义)
故x=1/2

Answer 2

1/2,应为logab乘以logba=1，所以同理，-log3x乘以log23等于1，即log31/x=log32,推出x=0.5

Answer 3

换底,
ln(x)/ln(3)=-1/[ln(3)/ln(2)]=-ln(2)/ln(3),
ln(x)=-ln(2)=ln(1/2),
x=1/2

Answer 4

1/2 -1/log2(3)=-log3(2)=log3(1/2) 所以X=1/2

Answer 5

log(3)x=-1/log(2)3
log(3)x=-log(3)2
log(3)x=log(3)2^(-1)
x=2^(-1)
x=1/2