Question

Java问题 为什么最后输入不了啊String CardName = input.nextLine(); 这里

import java.util.Scanner;
public class qwert {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Please enter today's date.(Example:28) ");
int date=input.nextInt();

// simulate it by randomly generate numbers
int cardNumber = (int)(Math.random() * 52);

System.out.print("The card you picked is ");
if (cardNumber % 13 == 0)
System.out.print("Ace of ");
else if (cardNumber % 13 == 10)
System.out.print("Jack of ");
else if (cardNumber % 13 == 11)
System.out.print("Queen of ");
else if (cardNumber % 13 == 12)
System.out.print("King of ");
else
System.out.print((cardNumber % 13) + " of ");
if (cardNumber / 13 == 0)
System.out.println("Clubs");
else if (cardNumber / 13 == 1)
System.out.println("Diamonds");
else if (cardNumber / 13 == 2)
System.out.println("Hearts");
else if (cardNumber / 13 == 3)
System.out.println("Spades");

//enter the card you have picked

System.out.println("Please enter the card you had picked(you should copy and paste):");
String CardName = input.nextLine();
//hearts
}
}

Answer 1

在你读取date的时候：int date=input.nextInt();其实你输入了date+\r\n，\r\n也就是你输入完date之后敲的回车，也就是说String CardName = input.nextLine();读到的是\r\n。
解决：只要在int date=input.nextInt();之后加上input.nextLine();就行了，把\r\n读掉

Answer 2

input.nextLine 是读标准输入，println是输出标准输出。
结果冲突了。
你在hearts部分再读一次就对了

Answer 3

麻烦说清楚一点你的问题，你试试改成这 String CardName = input.next();

Answer 4

把错误爆出来啊