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3个回答
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用平方差公式
(x^2-y)^2-(1-y)^2
=[(x^2-y)-(1-y)][(x^2-y)+(1-y)]
=(x^2-1)(x^2-2y+1)
=(x-1)(x+1)(x^2-2y+1)
(x^2-y)^2-(1-y)^2
=[(x^2-y)-(1-y)][(x^2-y)+(1-y)]
=(x^2-1)(x^2-2y+1)
=(x-1)(x+1)(x^2-2y+1)
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展开全部
1.(x^2-y)^2-(1-y)^2
平方差公式
=(x^2-y+1-y)(x^2-y-1+y)
=(x^2+1-2y)(x+1)(x-1)
2.(x^2+2x)^2-(2x+4)^2
=(x^2+2x+2x+4)(x^2+2x-2x-4)
=(x+2)^2(x+2)(x-2)
3.(x^2+2x)^2+2(x^2+2x)+1
=(x^2+2X+1)^2
=(x+1)^4
平方差公式
=(x^2-y+1-y)(x^2-y-1+y)
=(x^2+1-2y)(x+1)(x-1)
2.(x^2+2x)^2-(2x+4)^2
=(x^2+2x+2x+4)(x^2+2x-2x-4)
=(x+2)^2(x+2)(x-2)
3.(x^2+2x)^2+2(x^2+2x)+1
=(x^2+2X+1)^2
=(x+1)^4
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(x^2-y)^2-(1-y)^2
=(x²-y+1-y)(x²-y-1+y)
=(x²-2y+1)(x²-1)
=(x²-2y+1)(x+1)(x-1)
(x^2+2x)^2+2(x^2+2x)+1
=[(x²+2x)+1]²
=(x+2x+1)²
=[(x+1)²]²
=(x+1)^4
=(x²-y+1-y)(x²-y-1+y)
=(x²-2y+1)(x²-1)
=(x²-2y+1)(x+1)(x-1)
(x^2+2x)^2+2(x^2+2x)+1
=[(x²+2x)+1]²
=(x+2x+1)²
=[(x+1)²]²
=(x+1)^4
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