观察下面的算式,找出其中的规律,然后计算出最后一个算式的结果
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因为:1/6=1/2×3=1/2-1/3 1/12=1/3×4=1/3-1/4
所以:1/n(n+1)=1/n-1/n+1
即:1/2+1/6+1/12+1/20+1/30+······+1/110
=1/1×2+1/2×3+1/3×4+1/4×5+1/5×6+······+1/10×11
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)+······+(1/10-1/11)
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+······+1/10-1/11 去掉括号
=1-1/11 合并同类项
=10/11
=1-1/n+1 规律
希望采纳,有疑问追问。
所以:1/n(n+1)=1/n-1/n+1
即:1/2+1/6+1/12+1/20+1/30+······+1/110
=1/1×2+1/2×3+1/3×4+1/4×5+1/5×6+······+1/10×11
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)+······+(1/10-1/11)
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+······+1/10-1/11 去掉括号
=1-1/11 合并同类项
=10/11
=1-1/n+1 规律
希望采纳,有疑问追问。
来自:求助得到的回答
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