Question

4(a-b)的立方+2(b-a)平方-6(a-b)( )

x(b+c-d)-b-c+d( )

2(x+y)的平方-4(x+y) 因式分解

(b-a)的2n次方-(b-a)

Answer 1

4(a-b)的立方+2(b-a)平方-6(a-b)
=2(a-b)[2(a-b)²+(a-b)-3]
=2(a-b)(2a-2b-1)(a-b+3)

x(b+c-d)-b-c+d
=x(b+c-d)-(b+c-d)
=(b+c-d)(x-1)

2(x+y)的平方-4(x+y) 因式分解
=2(x+y)(x+y-2)

(b-a)的2n次方-(b-a)
=(b-a)[(b-a)的(2n-1)次方-1]