Question

关于x,y的多项式6mx^2+4nxy+2x+2xy-x^2+y+4不含二次项，求6m-2n+2的值

Answer 1

6mx^2+4nxy+2x+2xy-x^2+y+4

=（6m-1）x^2+(4n+2)xy+2x+y+4
不含二次项

所以二次项系数=0
即6m-1=4n+2=0
6m=1,4n=-2,2n=-1
所以6m-2n+2=1-(-1)+2=1+1+2=4

Answer 2

6mx^2+4nxy+2x+2xy-x^2+y+4

=(6m-1)x^2+(4n+2)xy+2x+y+4
不含二次项则系数为0

所以6m-1=0
4n+2=0
所以6m=1
2n=-1
所以原式=1+1+2=4

Answer 3

6mx^2+4nxy+2x+2xy-x^2+y+4

=（6m-1）x^2+(4n+2)xy+2x+y+4
不含二次项

所以二次项系数=0
即6m-1=4n+2=0
6m=1,4n=-2,2n=-1
所以6m-2n+2=1-(-1)+2=1+1+2=4如果满意请按下满意按钮！！！拜托！！！

Answer 4

6mx^2+4nxy+2x+2xy-x^2+y+4

=(6m-1)x^2+(4n+2)xy+2x+y+4
不含二次项则系数为0

所以6m-1=0
4n+2=0
所以6m=1
2n=-1
所以原式=1+1+2=4

所以
6m-2n+2=4

Answer 5

6mx^2+4nxy+2x+2xy-x^2+y+4
=（6m-1）x^2+（4n+2）xy+2x+y+4
因为多项式不含2次项，所以
6m-1=0,6m=1,4n+2=0,2n=-1
所以6m-2n+2=1+1+2=4