
(2x-y)的平方-3(2x-y)-4(2x-y)的平方+(2x-y),其中2x-y=-2和已知(x-y-2)的平方+x+y+1的绝对值=0,
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这是2道题吧
1
∵2x-y=-2
∴(2x-y)²-3(2x-y)-4(2x-y)²+(2x-y)
=-3(2x-y)²-2(2x-y)
=-3×(-2)²-2×(-2)
=-12+4
=-8
2
∵(x-y-2)²+|x+y+1|=0,
∴两非负项和为0,两项均为0
∴x-y-2=0,x+y+1=0
∴x-y=2,x+y=-1
∴(x-y)²+3(x+y)³-2(x-y)²-(x+y)³
=2(x+y)³-(x-y)²
=2×(-1)³-2²
=-6
1
∵2x-y=-2
∴(2x-y)²-3(2x-y)-4(2x-y)²+(2x-y)
=-3(2x-y)²-2(2x-y)
=-3×(-2)²-2×(-2)
=-12+4
=-8
2
∵(x-y-2)²+|x+y+1|=0,
∴两非负项和为0,两项均为0
∴x-y-2=0,x+y+1=0
∴x-y=2,x+y=-1
∴(x-y)²+3(x+y)³-2(x-y)²-(x+y)³
=2(x+y)³-(x-y)²
=2×(-1)³-2²
=-6
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