下面这道 数学微积分 求助！！！ ap，！！ 谢谢！！！
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V=∫(0,5) π(2+sinx)^2dx
=π∫(0,5)(4+4sinx+sin^2x)dx
=π(4x-4cosx)|(0,5)+π/2∫(0,5)(1-cos2x)dx
=4π[(5-0)-(cos5-cos0)]+π/2x|(0,5)-π/4∫(0,5)cos2xd(2x)
=20π-4πcos5+4π+π/2(5-0)-π/4sin2x|(0,5)
=26.5π-4π×0.2837-π/4(sin10-sin0)
=26.5π-1.1348π-π/4×(-0.5440)
=25.3652π+0.136π
=25.5012π
=80.07
选E
=π∫(0,5)(4+4sinx+sin^2x)dx
=π(4x-4cosx)|(0,5)+π/2∫(0,5)(1-cos2x)dx
=4π[(5-0)-(cos5-cos0)]+π/2x|(0,5)-π/4∫(0,5)cos2xd(2x)
=20π-4πcos5+4π+π/2(5-0)-π/4sin2x|(0,5)
=26.5π-4π×0.2837-π/4(sin10-sin0)
=26.5π-1.1348π-π/4×(-0.5440)
=25.3652π+0.136π
=25.5012π
=80.07
选E
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